4m^2-17m+15=0

Solution for 4m^2-17m+15=0 equation:

4m^2-17m+15=0

a = 4; b = -17; c = +15;
Δ = b2-4ac
Δ = -172-4·4·15
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-7}{2*4}=\frac{10}{8}
=1+1/4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+7}{2*4}=\frac{24}{8}
=3
$